numpy如何获取array中数组元素的索引位置

 

numpy - 获取array中数组元素的索引

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                                          <span class="time">2017年08月05日 10:36:59</span>
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1. 函数原型

argwhere(array)：找到非空数组array在满足某些条件下的索引，返回索引数组。

 

2. 应用

2.1 一维数组

返回一个一维数组，代表当前满足条件的元素出现的位置。

# -*- coding: utf-8 -*-  
import numpy as np  

arr = np.random.randint(0,10, (5,))  
index = np.argwhere(arr < 5)
# -*- coding: utf-8 -*-
import numpy as np

arr = np.random.randint(0,10, (5,))
index = np.argwhere(arr < 5)

2. 2 二维数组

返回二维数组，代表当前满足条件的元素出现的位置。

# -*- coding: utf-8 -*-  
import numpy as np  

”“” 
arr =  
  9 3 7 0  
  3 4 2 4  
  3 6 4 4  
   
index =  
  0   1 
  0   3 
  1   0 
  1   1 
  1   2 
  1   3 
  2   0 
  2   2 
  2   3 
”“”  
arr = np.random.randint(0,10, (3,4))  
index = np.argwhere(arr < 5)  
# -*- coding: utf-8 -*-
import numpy as np

"""
arr = 
  9 3 7 0 
  3 4 2 4 
  3 6 4 4 

index = 
  0   1
  0   3
  1   0
  1   1
  1   2
  1   3
  2   0
  2   2
  2   3
"""

arr = np.random.randint(0,10, (3,4))
index = np.argwhere(arr < 5)

参考文献

http://blog.csdn.net/vernice/article/details/50990919

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